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Acceleration for SQA National 5 Physics

Acceleration

This page covers the following topics:

1. Newtonโ€™s second law
2. Acceleration
3. Deceleration
4. Interpreting velocity-time graphs
5. Gradient of velocity-time graphs

Newton's second law states that the acceleration of an object is directly proportional to the resultant force in its direction and is inversely proportional to the mass of the object. It can be expressed using the following formula: resultant force = mass ร— acceleration. This equation can only be used when the acceleration of the moving object is constant.

Newtonโ€™s second law

Acceleration is the rate of change of velocity of an object. It is a vector quantity, as it is expressed by both magnitude and direction. It can be calculated using the following equation: acceleration = change in velocity รท time.

Acceleration

Deceleration is negative acceleration. It is calculated using the same equation as acceleration. A positive deceleration is a negative acceleration, with an example being a slowing down object.

Deceleration

A velocity-time graph is a graphical representation of an object's motion over a given period of time. The direction and the speed of an object can be deduced from the velocity-time graph of its motion. The area under the velocity-time graph of an object's motion gives its displacement.

Interpreting velocity-time graphs

The gradient of a velocity-time graph gives the acceleration of an object. A positive gradient shows that the object is accelerating, whereas a negative one shows that it is decelerating.

Gradient of velocity-time graphs

1

The velocity-time graph of an object's motion is drawn as a horizontal line. Explain what this says about the object's motion.

The object is travelling at constant velocity.

constant velocity

The velocity-time graph of an object's motion is drawn as a horizontal line. Explain what this says about the object's motion.

2

A car moving at a velocity of 30 m/s slows down to 18 m/s in 9 seconds. Calculate the deceleration of the car to 3 significant figures.

a = (v โˆ’ u)/t
a = (18 m/s โˆ’ 30 m/s)/9 s = โˆ’1.33 m/sยฒ (to 3 significant figures)
Therefore, the deceleration of the object is 1.33 m/sยฒ.

1.33 m/sยฒ

A car moving at a velocity of 30 m/s slows down to 18 m/s in 9 seconds. Calculate the deceleration of the car to 3 significant figures.

3

An object is travelling at a constant velocity of 15 m/s for the first 6 seconds of its motion and then it slows down at a constant rate to rest in a further 5 seconds. Draw a velocity-time graph for this object.

The y axis of the graph is velocity in m/s and the x axis is time in seconds.
The object travels at a 15 m/s velocity for 6 seconds.
The object then decelerates to rest in a further 5 seconds.

image

An object is travelling at a constant velocity of 15 m/s for the first 6 seconds of its motion and then it slows down at a constant rate to rest in a further 5 seconds. Draw a velocity-time graph for this object.

4

A car is travelling in a straight line at a constant velocity of 10 m/s when it starts to accelerate. After 5 seconds, the velocity of the car is 14 m/s. Calculate the magnitude of the acceleration of the car.

a = (v โˆ’ u) รท t
acceleration = (14 m/s โˆ’ 10 m/s) รท 5 s = 0.8 m/sยฒ

0.8 m/sยฒ

A car is travelling in a straight line at a constant velocity of 10 m/s when it starts to accelerate. After 5 seconds, the velocity of the car is 14 m/s. Calculate the magnitude of the acceleration of the car.

5

Plot a labelled velocity-time graph for an object travelling at a constant rate of 17 m/s for 2 seconds and then accelerates for 5 seconds at a rate of 1 m/sยฒ and travels at this new velocity for a further 3 seconds.

The y axis of the graph is velocity in m/s and the x axis is time in seconds.
The object travels at a 17 m/s velocity for 2 seconds.
The object then accelerates to 17 m/s + 5 ร— 1m/sยฒ = 22 m/s in 5 seconds.
The object continues travelling at a constant 22 m/s velocity for another 3 seconds.

image

Plot a labelled velocity-time graph for an object travelling at a constant rate of 17 m/s for 2 seconds and then accelerates for 5 seconds at a rate of 1 m/sยฒ and travels at this new velocity for a further 3 seconds.

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