
StudySquare
Redox equations for Edexcel GCSE Chemistry







This page covers the following topics:
1. Redox half-equations
2. Reactivity of halogens
Reduction is the gain of electrons or the decrease of an oxidation number. Oxidation is the loss of electrons or the increase of the oxidation number. A particle gains electrons when it is reduced and a particle loses electrons when it is oxidised. Redox half-equations provide information about the change in particles and the loss or gain of electrons. Many half-equations can be balanced by adding electrons, water molecules and hydrogen ions.
Fe³⁺ + e⁻ → Fe²⁺ (reduction)
Mg → Mg²⁺ + 2e⁻ (oxidation)

The reactivity of halogens decreases going down the group 7 of the periodic table. A more reactive halogen displaces a less reactive halogen in a halide salt solution.

1
Explain why iodine does not displace chlorine in sodium chloride that is dissolved in water.
A more reactive halogen displaces a less reactive halogen in halide salt solutions. The reactivity of halogens decreases going down the group 7 of the periodic table. Since iodine is lower down the group 7 than chlorine, it it is less reactive and does not displace chlorine in its salt.
Iodine is less reactive than chlorine.

2
Identify all particles that are reduced in the half-equations provided.
2Cl⁻ → Cl₂ + 2e⁻
Mn⁵⁺ + 3e⁻ → Mn²⁺
A particle gains electrons when it is reduced. In these half-equations Mn⁵⁺ gains electrons.
Mn⁵⁺
3
Provide a balanced chemical equation for the reaction that happens when chlorine is added to a calcium iodide solution.
A more reactive halogen displaces a less reactive halogen in halide salt solutions. Chlorine is more reactive than iodine, thus chlorine displaces iodine in the salt.
CaI₂ + Cl₂ → CaCl₂ + I₂
4
Provide a balanced chemical equation for the reaction between fluorine and lithium bromide solution.
A more reactive halogen displaces a less reactive halogen in halide salt solutions. Fluorine is more reactive than bromine, thus fluorine displaces bromine in the salt.
2LiBr + F₂ → 2LiF + Br₂
5
Balance the half-equation provided.
MnO₄⁻ + H⁺ + e⁻ → Mn²⁺ + H₂O
MnO₄⁻ + H⁺ + e⁻ → Mn²⁺ + 4H₂O
MnO₄⁻ + 8H⁺ + e⁻ → Mn²⁺ + 4H₂O
MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
MnO₄⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H₂O
End of page